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x^2=250000
We move all terms to the left:
x^2-(250000)=0
a = 1; b = 0; c = -250000;
Δ = b2-4ac
Δ = 02-4·1·(-250000)
Δ = 1000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1000000}=1000$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-1000}{2*1}=\frac{-1000}{2} =-500 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+1000}{2*1}=\frac{1000}{2} =500 $
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